Theory of Intelligence
11TH•Mathematics•Sequences And Series•Exercise 6.5

6.5 Geometric Progression (G.P.)

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Question 1

Find the 6th term of the G.P.: −6, −3, −32, …-6,\ -3,\ -\dfrac{3}{2},\ \ldots.

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Question 1

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G.P.: (-6,\ -3,\ -\dfrac{3}{2},\ \ldots)

(a=-6), (r=\dfrac{-3}{-6}=\dfrac{1}{2})

[ a_6 = ar^5 = -6\cdot\left(\dfrac{1}{2}\right)^5 = -6\cdot\dfrac{1}{32} = -\dfrac{3}{16} ]

Answer: (-\dfrac{3}{16})

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