Given: f(x)=2x+3f(x) = \sqrt{2x + 3}f(x)=2x+3 Replace xxx with (x2+3)(x^2 + 3)(x2+3): f(x2+3)=2(x2+3)+3=2x2+6+3=2x2+9\begin{aligned} f(x^2 + 3) &= \sqrt{2(x^2 + 3) + 3} \\ &= \sqrt{2x^2 + 6 + 3} \\ &= \sqrt{2x^2 + 9} \end{aligned}f(x2+3)=2(x2+3)+3=2x2+6+3=2x2+9 f(x2+3)=2x2+9\boxed{f(x^2 + 3) = \sqrt{2x^2 + 9}}f(x2+3)=2x2+9