Given: f(x)=2x+3f(x) = \sqrt{2x + 3}f(x)=2x+3 Replace xxx with (x−2)(x - 2)(x−2): f(x−2)=2(x−2)+3=2x−4+3=2x−1\begin{aligned} f(x - 2) &= \sqrt{2(x - 2) + 3} \\ &= \sqrt{2x - 4 + 3} \\ &= \sqrt{2x - 1} \end{aligned}f(x−2)=2(x−2)+3=2x−4+3=2x−1 f(x−2)=2x−1\boxed{f(x - 2) = \sqrt{2x - 1}}f(x−2)=2x−1