Given: f(x)=2x+3f(x) = \sqrt{2x + 3}f(x)=2x+3 Substitute x=0x = 0x=0: f(0)=2(0)+3=0+3=3\begin{aligned} f(0) &= \sqrt{2(0) + 3} \\ &= \sqrt{0 + 3} \\ &= \sqrt{3} \end{aligned}f(0)=2(0)+3=0+3=3 f(0)=3\boxed{f(0) = \sqrt{3}}f(0)=3