Given: f(x)=x2−1f(x) = x^2 - 1f(x)=x2−1 Replace xxx with (x−2)(x - 2)(x−2): f(x−2)=(x−2)2−1=(x2−4x+4)−1=x2−4x+3\begin{aligned} f(x - 2) &= (x - 2)^2 - 1 \\ &= (x^2 - 4x + 4) - 1 \\ &= x^2 - 4x + 3 \end{aligned}f(x−2)=(x−2)2−1=(x2−4x+4)−1=x2−4x+3 f(x−2)=x2−4x+3\boxed{f(x - 2) = x^2 - 4x + 3}f(x−2)=x2−4x+3