G.M. = 4, H.M. = (\dfrac{16}{5})
[ \sqrt{xy}=4\implies xy=16 ] [ \dfrac{2xy}{x+y}=\dfrac{16}{5}\implies\dfrac{32}{x+y}=\dfrac{16}{5}\implies x+y=10 ]
[ t^2-10t+16=0\implies(t-8)(t-2)=0 ]
Answer: 2 and 8
11TH•Mathematics•Sequences And Series•Question 9
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If the (positive) G.M. and H.M. between two numbers are 4 and $\dfrac{16}{5}$, find the numbers.
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