H.M. = 4, A.M. = (\dfrac{9}{2})
[ \dfrac{x+y}{2}=\dfrac{9}{2}\implies x+y=9 ] [ \dfrac{2xy}{x+y}=4\implies\dfrac{2xy}{9}=4\implies xy=18 ]
[ t^2-9t+18=0\implies(t-6)(t-3)=0 ]
Answer: 3 and 6
11TH•Mathematics•Sequences And Series•Question 8
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If the H.M. and A.M. between two numbers are 4 and $\dfrac{9}{2}$ respectively, find the numbers.
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