(i)
[ \dfrac{a-b}{b-c}=\dfrac{a-\frac{2ac}{a+c}}{\frac{2ac}{a+c}-c}=\dfrac{\frac{a(a+c)-2ac}{a+c}}{\frac{2ac-c(a+c)}{a+c}}=\dfrac{a^2-ac}{2ac-ac-c^2}=\dfrac{a(a-c)}{c(a-c)}=\dfrac{a}{c} ]
11TH•Mathematics•Sequences And Series•Question 16
(i)
If $a,\ b,\ c$ are in H.P., show that
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