Solution Let u=x2u = x^2u=x2: u2−10u+9=0(u−1)(u−9)=0u=1oru=9\begin{aligned} u^2 - 10u + 9 &= 0 \\ (u - 1)(u - 9) &= 0 \\ u = 1 \quad&\text{or}\quad u = 9 \end{aligned}u2−10u+9(u−1)(u−9)u=1=0=0oru=9 Convert back: x2=1x^2 = 1x2=1 gives x=±1x = \pm 1x=±1, and x2=9x^2 = 9x2=9 gives x=±3x = \pm 3x=±3. x=−3, −1, 1, 3x = -3,\ -1,\ 1,\ 3x=−3, −1, 1, 3