4.4 Power
In the definition of work, it is not clear, whether the same amount of work is done in one second or in one hour. The rate, at which work is done, is often of interest in practical applications.
Power is the measure of the rate at which work is being done.
If work ΔW is done in a time interval Δt, then the average power Pav during the interval Δt is defined as:
Pav=ΔtΔW…(4.6)
If work is expressed as a function of time, the instantaneous power P at any instant is defined as:
P=Δt→0limΔtΔW…(4.7)
where ΔW is the work done in short interval of time Δt.
Since ΔW=F⋅Δd
Hence P=(F⋅Δd)/Δt=F⋅(Δd/Δt)
Since Δd/Δt=v
Hence
P=F⋅v…(4.8)
Thus, power may also be defined as the scalar product of F and v.
The SI unit of power is watt, defined as one joule of work done in one second.
Sometimes, for example, in the electrical measurements, the unit of work is expressed as watt second. However, a commercial unit of electrical energy is kilowatt-hour.
One kilowatt-hour is the work done in one hour by an agency whose power is one kilowatt.
Therefore
1kW⋅h=1000W×3600s
or
1kW⋅h=3.6×106J=3.6MJ
For your information — Approximate Power
| Device | Approximate Power (W) |
|---|
| Jumbo Jet Aircraft | 1.3×104 |
| Car at 90km/h | 1.1×103 |
| Electric heater | 2×103 |
| Coloured TV | 120 |
Example 4.2
A 70kg man runs up a long flight of stairs in 4.0s. The vertical height of the stairs is 4.5m. Calculate his power output in watts.
Solution
Work done =mgh
Power P=mgh/t
P=4s(70kg×9.8m/s2×4.5m)
P=7.7×103kgm/s3=7.7×103W