Theory of Intelligence
11TH•Mathematics•Theory Of Quadratic Functions•Question 2

Step-by-Step Solution

Find the maximum or minimum point by sketching the following quadratic functions. Also find their domain and range:

Step-by-Step Solution

Step 1: Identify Parameters and Vertex

For f(x)=ax2+bx+cf(x) = ax^2 + bx + c:

a=−1,b=2,c=−8a = -1, \quad b = 2, \quad c = -8

Since a=−1<0a = -1 < 0, the parabola opens downwards, meaning the vertex is an absolute maximum point.

The xx-coordinate of the vertex hh:

h=−b2a=−22(−1)=1h = -\frac{b}{2a} = -\frac{2}{2(-1)} = 1

The yy-coordinate kk:

k=f(1)=−(1)2+2(1)−8=−1+2−8=−7k = f(1) = -(1)^2 + 2(1) - 8 = -1 + 2 - 8 = -7

The vertex is (1,−7)(1, -7).

Step 2: Intercepts & Discriminant

  • yy-intercept: f(0)=−8  ⟹  (0,−8)f(0) = -8 \implies (0, -8).
  • Discriminant: Δ=b2−4ac=(2)2−4(−1)(−8)=4−32=−28<0\Delta = b^2 - 4ac = (2)^2 - 4(-1)(-8) = 4 - 32 = -28 < 0. Because the discriminant is negative and a<0a < 0, the parabola lies entirely below the xx-axis and has no real xx-intercepts.
  • Axis of Symmetry: x=1x = 1

Step 3: Domain and Range

  • Domain: Defined for every real number: Domain=R=(−∞,∞)\text{Domain} = \mathbb{R} = (-\infty, \infty)
  • Range: Since the maximum peak is at y=−7y = -7 and the parabola extends downwards to −∞-\infty: Range=(−∞,−7]\text{Range} = (-\infty, -7]

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