G.P.: (-6,\ -3,\ -\dfrac{3}{2},\ \ldots)
(a=-6), (r=\dfrac{-3}{-6}=\dfrac{1}{2})
[ a_6 = ar^5 = -6\cdot\left(\dfrac{1}{2}\right)^5 = -6\cdot\dfrac{1}{32} = -\dfrac{3}{16} ]
Answer: (-\dfrac{3}{16})
11TH•Mathematics•Sequences And Series•Question 1
Overview
Find the 6th term of the G.P.: $-6,\ -3,\ -\dfrac{3}{2},\ \ldots$.
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