Half-life = 5 years. After 20 years there have been ( \dfrac{20}{5} = 4 ) half-lives.
[ 68 = A_0 \left(\frac12\right)^4 = A_0 \cdot \frac{1}{16} \implies A_0 = 68 \times 16 = 1088. ]
Answer: 1088 microcuries
11TH•Mathematics•Sequences And Series•Question 12
Overview
A radioactive product has a half life of 5 years. If the radioactivity level is 68 microcuries after 20 years. Determine the original level of radioactivity.
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