(vi) 11×2+12×3+13×4+⋯+1n(n+1)=1−1n+1\dfrac{1}{1\times 2} + \dfrac{1}{2\times 3} + \dfrac{1}{3\times 4} + \cdots + \dfrac{1}{n(n+1)} = 1 - \dfrac{1}{n+1}1×21+2×31+3×41+⋯+n(n+1)1=1−n+11