Theory of Intelligence
10TH•Mathematics•Vectors•6.3–6.5 Addition, Difference and Components

6.3 Addition of Vectors

Triangle and parallelogram laws, vector difference, coplanar components; EXERCISE 6.2.

6.3 Addition of Vectors

(i) Triangle Law of Addition:

If two vectors u‾\underline{u} and v‾\underline{v} are represented by the two adjacent sides AB→\overrightarrow{AB} and BC→\overrightarrow{BC} of a triangle such that the terminal point of u‾\underline{u} coincides with the initial point of v‾\underline{v}, then the third side AC→\overrightarrow{AC} of the triangle gives the vector sum u‾+v‾\underline{u} + \underline{v} that is:

AB→+BC→=AC→⇒u‾+v‾=AC→\overrightarrow{AB} + \overrightarrow{BC} = \overrightarrow{AC} \Rightarrow \underline{u} + \underline{v} = \overrightarrow{AC}

By head to tail rule

[Figure 6.9]

(ii) Parallelogram Law of Addition:

If two vectors u‾\underline{u} and v‾\underline{v} are represented by two adjacent sides AB→\overrightarrow{AB} and AC→\overrightarrow{AC} of a parallelogram as shown in the Figure 6.10, then diagonal AD→\overrightarrow{AD} gives the sum or resultant of AB→\overrightarrow{AB} and AC→\overrightarrow{AC}.

AD→=AB→+AC→\overrightarrow{AD} = \overrightarrow{AB} + \overrightarrow{AC}

AD→=u‾+v‾\overrightarrow{AD} = \underline{u} + \underline{v}

[Figure 6.10]

Example 6

If a‾=2i‾+3j‾,b‾=4i‾−6j‾\underline{a} = 2\underline{i} + 3\underline{j}, \underline{b} = 4\underline{i} - 6\underline{j}, then find a‾+b‾\underline{a} + \underline{b}.

Solution a‾+b‾=(2i‾+3j‾)+(4i‾−6j‾)\underline{a} + \underline{b} = (2\underline{i} + 3\underline{j}) + (4\underline{i} - 6\underline{j})

=(2+4)i‾+(3−6)j‾= (2 + 4)\underline{i} + (3 - 6)\underline{j}

=6i‾−3j‾= 6\underline{i} - 3\underline{j}

lightbulb

Skilled Practice!
If a‾=10i‾−12j‾,b‾=34i‾−76j‾\underline{a} = 10\underline{i} - \dfrac{1}{2}\underline{j}, \underline{b} = \dfrac{3}{4}\underline{i} - \dfrac{7}{6}\underline{j}, then find a‾+b‾\underline{a} + \underline{b}.

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