Theory of Intelligence
12TH•Physics•Electrostatics•Question 6

Solution

Two capacitors of $2.0\,\mu\mathrm{F}$ and $8.0\,\mu\mathrm{F}$ capacitances are connected in series and a potential difference of $300$ volts is applied. Find the charge and potential difference for each capacitor.

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Solution

Q1=Q2=4.8×10−4 C,V1=240 V,V2=60 VQ_{1} = Q_{2} = 4.8 \times 10^{-4}\,\mathrm{C},\quad V_{1} = 240\,\mathrm{V},\quad V_{2} = 60\,\mathrm{V}

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