11TH•Physics•Nuclear And Particle Physics•Question 4

Solution

Show that nucleon number $N$ and charge number $Z$ are conserved in the numerical question $12.3$.

The reaction of question $12.3$ is

{}^{14}_{7}\mathrm{N} + {}^{4}_{2}\mathrm{He} \rightarrow {}^{17}_{8}\mathrm{O} + {}^{1}_{1}\mathrm{H}

Nucleon number: $14 + 4 = 18$ and $17 + 1 = 18$ .

Charge number: $7 + 2 = 9$ and $8 + 1 = 9$ .

Both nucleon number $N$ and charge number $Z$ are conserved.

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