(v) 1+sinα1−sinα=sinα2+cosα2sinα2−cosα2\sqrt{\dfrac{1 + \sin\alpha}{1 - \sin\alpha}} = \dfrac{\sin\dfrac{\alpha}{2} + \cos\dfrac{\alpha}{2}}{\sin\dfrac{\alpha}{2} - \cos\dfrac{\alpha}{2}}1−sinα1+sinα=sin2α−cos2αsin2α+cos2α