Theory of Intelligence
11TH•Mathematics•Trigonometric Identities•Question 6

(i)

Show that:

(i)

sin⁡2(α+β2)−sin⁡2(α−β2)=sin⁡2αsin⁡β\sin^2\left(\alpha + \dfrac{\beta}{2}\right) - \sin^2\left(\alpha - \dfrac{\beta}{2}\right) = \sin 2\alpha \sin\beta

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