(v) 1−tanθtanϕ1+tanθtanϕ=cos(θ+ϕ)cos(θ−ϕ)\dfrac{1 - \tan\theta \tan\phi}{1 + \tan\theta \tan\phi} = \dfrac{\cos(\theta + \phi)}{\cos(\theta - \phi)}1+tanθtanϕ1−tanθtanϕ=cos(θ−ϕ)cos(θ+ϕ)