(i) tan(180∘+α)cot(90∘−α)sin(360∘−α)cos(270∘+α)=−sec2α\dfrac{\tan(180^\circ + \alpha)\cot(90^\circ - \alpha)}{\sin(360^\circ - \alpha)\cos(270^\circ + \alpha)} = -\sec^2\alphasin(360∘−α)cos(270∘+α)tan(180∘+α)cot(90∘−α)=−sec2α