Theory of Intelligence
11TH•Mathematics•Trigonometric Identities•10.3 Further Applications of Basic Identities

10.3 Further Applications of Basic Identities

Product identities, compound-angle evaluations, and triangle formulas.

10.3 Further Applications of Basic Identities

Example 5

Prove sin⁡(α+β)sin⁡(α−β)=sin⁡2α−sin⁡2β=cos⁡2β−cos⁡2α\sin(\alpha+\beta)\sin(\alpha-\beta) = \sin^2\alpha - \sin^2\beta = \cos^2\beta - \cos^2\alpha.

Expand as a difference of squares in sin⁡αcos⁡β\sin\alpha\cos\beta and cos⁡αsin⁡β\cos\alpha\sin\beta, then rewrite using 1−sin⁡21 - \sin^2 / 1−cos⁡21 - \cos^2.

Example 6

All six trig functions of 105∘=60∘+45∘105^\circ = 60^\circ + 45^\circ:

sin⁡105∘=3+122,cos⁡105∘=1−322,tan⁡105∘=1+31−3\sin 105^\circ = \dfrac{\sqrt{3}+1}{2\sqrt{2}},\quad \cos 105^\circ = \dfrac{1-\sqrt{3}}{2\sqrt{2}},\quad \tan 105^\circ = \dfrac{1+\sqrt{3}}{1-\sqrt{3}}

and reciprocals for cot⁡\cot, cosec⁡\operatorname{cosec}, sec⁡\sec.

Example 7

cos⁡11∘+sin⁡11∘cos⁡11∘−sin⁡11∘=tan⁡56∘\dfrac{\cos 11^\circ + \sin 11^\circ}{\cos 11^\circ - \sin 11^\circ} = \tan 56^\circ

(Write tan⁡56∘=tan⁡(45∘+11∘)\tan 56^\circ = \tan(45^\circ+11^\circ) and simplify.)

Example 8

Given cos⁡α=−725\cos\alpha = -\dfrac{7}{25} (Quad II) and tan⁡β=125\tan\beta = \dfrac{12}{5} (Quad III):

sin⁡α=2425\sin\alpha = \dfrac{24}{25}, cos⁡β=−513\cos\beta = -\dfrac{5}{13}, sin⁡β=−1213\sin\beta = -\dfrac{12}{13}.

sin⁡(α+β)=−36325,cos⁡(α+β)=323325\sin(\alpha+\beta) = -\dfrac{36}{325},\quad \cos(\alpha+\beta) = \dfrac{323}{325}

Terminal arm of α+β\alpha+\beta lies in Quad IV.

Example 9

In △ABC\triangle ABC, α+β+γ=180∘\alpha+\beta+\gamma = 180^\circ:

(i) tan⁡α+tan⁡β+tan⁡γ=tan⁡αtan⁡βtan⁡γ\tan\alpha + \tan\beta + \tan\gamma = \tan\alpha\tan\beta\tan\gamma

(ii) tan⁡α2tan⁡β2+tan⁡β2tan⁡γ2+tan⁡γ2tan⁡α2=1\tan\dfrac{\alpha}{2}\tan\dfrac{\beta}{2} + \tan\dfrac{\beta}{2}\tan\dfrac{\gamma}{2} + \tan\dfrac{\gamma}{2}\tan\dfrac{\alpha}{2} = 1

Example 10

3sin⁡θ+4cos⁡θ=5sin⁡(θ+ϕ)3\sin\theta + 4\cos\theta = 5\sin(\theta + \phi) where tan⁡ϕ=43\tan\phi = \dfrac{4}{3} and ϕ\phi is in Quad I (r=5r = 5, rcos⁡ϕ=3r\cos\phi = 3, rsin⁡ϕ=4r\sin\phi = 4).

Discuss theoretical concepts, mathematical formulas, and architectural foundations.

Supports inline code with `backticks`
No comments yet. Be the first to start the discussion!