Theory of Intelligence
11TH•Mathematics•Theory Of Quadratic Functions•Question 4

Step-by-Step Solution

Solve the following absolute value quadratic equations and inequalities:

Step-by-Step Solution

Step 1: Analyze the Argument of the Absolute Value

Notice that for all real numbers x∈Rx \in \mathbb{R}:

x2≥0  ⟹  x2+1≥1>0x^2 \ge 0 \implies x^2 + 1 \ge 1 > 0

Because the expression inside the absolute value bars is strictly positive for every real xx, the absolute value bars have no effect:

∣x2+1∣=x2+1|x^2 + 1| = x^2 + 1

Step 2: Solve the Simplified Algebraic Equation

Equating the simplified expression to 55:

x2+1=5x2=4x=±4=±2\begin{aligned} x^2 + 1 &= 5 \\ x^2 &= 4 \\ x &= \pm\sqrt{4} = \pm 2 \end{aligned}

Step 3: Graphical Interpretation

The parabola y=x2+1y = x^2 + 1 lies entirely above the xx-axis. It intersects the horizontal line y=5y = 5 at two symmetric points: (−2,5)(-2, 5) and (2,5)(2, 5).


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