Theory of Intelligence
11TH•Mathematics•Theory Of Quadratic Functions•Question 1

Step-by-Step Solution

Find the maximum or minimum value of the following quadratic functions by completing square:

Step-by-Step Solution

Step 1: Analyze the Leading Coefficient

Comparing with f(x)=ax2+bx+cf(x) = ax^2 + bx + c:

a=−2,b=−1,c=21a = -2, \quad b = -1, \quad c = 21

Because a=−2<0a = -2 < 0, the parabola opens downwards (∩\cap). Therefore, the function achieves an absolute maximum value at its vertex.

Step 2: Complete the Square

Factor out the leading coefficient −2-2 from the xx-terms:

f(x)=−2(x2+12x)+21f(x) = -2\left(x^2 + \frac{1}{2}x\right) + 21

Complete the square inside the parenthesis by adding (14)2=116\left(\frac{1}{4}\right)^2 = \frac{1}{16}. Adding 116\frac{1}{16} inside corresponds to adding −2×116=−18-2 \times \frac{1}{16} = -\frac{1}{8}, so we must add 18\frac{1}{8} outside:

f(x)=−2(x2+12x+116)+21+18=−2(x+14)2+168+18=−2(x+14)2+1698\begin{aligned} f(x) &= -2\left(x^2 + \frac{1}{2}x + \frac{1}{16}\right) + 21 + \frac{1}{8} \\ &= -2\left(x + \frac{1}{4}\right)^2 + \frac{168 + 1}{8} \\ &= -2\left(x + \frac{1}{4}\right)^2 + \frac{169}{8} \end{aligned}

Step 3: Determine the Extremum Point

Because −2(x+14)2≤0-2\left(x + \frac{1}{4}\right)^2 \le 0 for all real numbers xx, the maximum is achieved when:

x+14=0  ⟹  x=−14=−0.25x + \frac{1}{4} = 0 \implies x = -\frac{1}{4} = -0.25

Step 4: Calculate the Maximum Value

Substituting x=−14x = -\frac{1}{4}:

f(−14)=−2(0)2+1698=1698=21.125f\left(-\frac{1}{4}\right) = -2(0)^2 + \frac{169}{8} = \frac{169}{8} = 21.125

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