6, 11, 16 are three A.Ms between (a) and (b).
Sequence: (a,\ 6,\ 11,\ 16,\ b) (5 terms)
[ d = 11 - 6 = 5 ]
[ 6 = a + d \implies a = 1 ] [ b = 16 + d = 21 ]
Answer: (a = 1,\ b = 21)
11TH•Mathematics•Sequences And Series•Question 2
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If 6, 11, 16 are three A.Ms. between $a$ and $b$, find $a$ and $b$.
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