Theory of Intelligence
11TH•Mathematics•Matrices And Determinants•Question 3

Part (ii): Distributivity $A(B + C) = AB + AC$

If $A=\begin{bmatrix}-i&2i\\1&-i\end{bmatrix}$, $B=\begin{bmatrix}-i&1\\2i&1\end{bmatrix}$ and $C=\begin{bmatrix}2i&2i\\-i&i\end{bmatrix}$, then show that:

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Part (ii): Distributivity A(B+C)=AB+ACA(B + C) = AB + AC

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