Theory of Intelligence
11TH•Mathematics•Mathematical Inductions And Binomial Theorem•8.2 Binomial Theorem

8.2 Binomial Theorem

Binomial theorem for positive integral index, general term, and middle terms.

8.2 Binomial Theorem

A binomial has two terms (e.g. a+ba+b). For positive integer nn:

(a+b)n=∑r=0n(nr)an−rbr(a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r

Proved by induction using Pascal's identity (kr)+(kr−1)=(k+1r)\binom{k}{r} + \binom{k}{r-1} = \binom{k+1}{r}.

Observations:

  1. Number of terms =n+1= n+1.
  2. Exponents of aa and bb in each term sum to nn.
  3. (nr)=(nn−r)\binom{n}{r} = \binom{n}{n-r} (symmetric coefficients).
  4. General term: Tr+1=(nr)an−rbrT_{r+1} = \binom{n}{r} a^{n-r} b^r.

Example 13

Expand (a2−2a)6\bigl(\dfrac{a}{2} - \dfrac{2}{a}\bigr)^6; general term Tr+1=(−1)r(6r)(a2)6−2rT_{r+1} = (-1)^r \binom{6}{r} \bigl(\dfrac{a}{2}\bigr)^{6-2r}.

Example 14

(9.9)5=(10−0.1)5≈95099.00499(9.9)^5 = (10-0.1)^5 \approx 95099.00499.

Example 15

In (32x−13x)11\bigl(\dfrac{3}{2}x - \dfrac{1}{3x}\bigr)^{11}:

  • Term in x5x^5: T4=−40095256x5T_4 = -\dfrac{40095}{256}x^5
  • Fifth term: T5=445564x3T_5 = \dfrac{4455}{64}x^3
  • Sixth from end: T7=7716xT_7 = \dfrac{77}{16x}

Discuss theoretical concepts, mathematical formulas, and architectural foundations.

Supports inline code with `backticks`
No comments yet. Be the first to start the discussion!