Theory of Intelligence
11TH•Mathematics•Complex Numbers•Question 3

Solution

Find roots and express as a product of linear factors: $z^4 + 7z^2 - 144 = 0$ .

Solution

Let u=z2 to form a quadratic equation:z4+7z2−144=0  ⟹  u2+7u−144=0Quadratic formula: u=−b±b2−4ac2au=−7±49−4(1)(−144)2(1)=−7±49+5762=−7±6252=−7±252u=−7+252=182=9oru=−7−252=−322=−16Since u=z2, we have z2=9 or z2=−16z2=9  ⟹  z=±3z2=−16  ⟹  z=±4i(since −16=±4i)Therefore, the roots are: 3,−3,4i,−4iUsing the factor theorem:z4+7z2−144=(z−3)(z+3)(z−4i)(z+4i)\begin{aligned} & \boxed{\text{Let } u = z^2 \text{ to form a quadratic equation:}} \\ \\ & z^4 + 7z^2 - 144 = 0 \implies u^2 + 7u - 144 = 0 \\ \\ & \boxed{\text{Quadratic formula: } u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}} \\ \\ & u = \frac{-7 \pm \sqrt{49 - 4(1)(-144)}}{2(1)} = \frac{-7 \pm \sqrt{49 + 576}}{2} = \frac{-7 \pm \sqrt{625}}{2} = \frac{-7 \pm 25}{2} \\ \\ & u = \frac{-7 + 25}{2} = \frac{18}{2} = 9 \quad \text{or} \quad u = \frac{-7 - 25}{2} = \frac{-32}{2} = -16 \\ \\ & \boxed{\text{Since } u = z^2 \text{, we have } z^2 = 9 \text{ or } z^2 = -16} \\ \\ & z^2 = 9 \implies z = \pm 3 \\ \\ & z^2 = -16 \implies z = \pm 4i \quad (\text{since } \sqrt{-16} = \pm 4i) \\ \\ & \boxed{\text{Therefore, the roots are: } 3, -3, 4i, -4i} \\ \\ & \boxed{\text{Using the factor theorem:}} \\ \\ & z^4 + 7z^2 - 144 = (z - 3)(z + 3)(z - 4i)(z + 4i) \end{aligned}

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