Theory of Intelligence
11TH•Mathematics•Sequences And Series•Question 4

(i) \(1+(a+b)+(a^2+ab+b^2)+(a^3+a^2b+ab^2+b^3)+\cdots\)

Sum to $n$ terms the series:

(i) (1+(a+b)+(a^2+ab+b^2)+(a^3+a^2b+ab^2+b^3)+\cdots)

(n^{th}) term (= \dfrac{a^n-b^n}{a-b}) (if (a\neq b))

[ S_n = \sum_{k=0}^{n-1}\dfrac{a^k-b^k}{a-b} = \dfrac{1}{a-b}\left[\dfrac{a^n-1}{a-1}-\dfrac{b^n-1}{b-1}\right] ] (assuming (a,b\neq1); special cases handled separately)

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