(i) (a_1=4), (n=25), (a_n=100)
[ S_n = \dfrac{n}{2}(a_1+a_n) = \dfrac{25}{2}(4+100) = \dfrac{25}{2}\cdot104 = 1300 ]
Answer: (1300)
Find $S_n$ for each arithmetic series:
[ S_n = \dfrac{n}{2}(a_1+a_n) = \dfrac{25}{2}(4+100) = \dfrac{25}{2}\cdot104 = 1300 ]
Answer: (1300)
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