(i) ( n^3 - n )
[ n^3 - n = n(n^2 - 1) = n(n-1)(n+1) = (n+1)n(n-1) = \dfrac{(n+1)!}{(n-2)!}. ]
(Alternatively ( n(n-1)(n+1) ).)
Answer: ( \dfrac{(n+1)!}{(n-2)!} )
11TH•Mathematics•Permutations And Combinations•Question 2
(i) \( n^3 - n \)
Write each of the following in the factorial form:
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