Solution Using Cramer’s rule for AX=BAX=BAX=B (with ∣A∣≠0|A|\ne 0∣A∣=0): x=∣Ax∣∣A∣,y=∣Ay∣∣A∣,z=∣Az∣∣A∣x=\frac{|A_x|}{|A|},\qquad y=\frac{|A_y|}{|A|},\qquad z=\frac{|A_z|}{|A|}x=∣A∣∣Ax∣,y=∣A∣∣Ay∣,z=∣A∣∣Az∣